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9y^2=24-19y
We move all terms to the left:
9y^2-(24-19y)=0
We add all the numbers together, and all the variables
9y^2-(-19y+24)=0
We get rid of parentheses
9y^2+19y-24=0
a = 9; b = 19; c = -24;
Δ = b2-4ac
Δ = 192-4·9·(-24)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-35}{2*9}=\frac{-54}{18} =-3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+35}{2*9}=\frac{16}{18} =8/9 $
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